### Discussion :: Average - General Questions (Q.No.8)

Renu said: (Oct 4, 2010) | |

Question: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died? Can anyone help me to find solution for this question AS SOON AS POSSIBLE? |

Sundar said: (Oct 5, 2010) | |

@Renu The solution for your problem: Lets take the age of father 10 yrs ago as x. Then rest of the 5 members 10 yrs ago as y. Now the mean age 10 yrs ago is = (x + y)/6 --(1) and now as father is dead and all the ages of the other 5 members has risen by 10 each. So mean age now =(y + 5(10))/6 ---(2) Equating (1) and (2): (x+y)/6 = (y+50)/6 Be solving the above, we get x = 50. So present age when he died = x + 10 = 60 yrs. |

Vinod said: (Nov 29, 2010) | |

Ques- The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is: , ... Can anybody explain it easily. because i don't understand that why we took this condition - Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years. |

Praveen said: (Nov 30, 2010) | |

@vinod .. h+w+c - w+c =husbands age 27*3 here 27 is average age and 3 is the number (sum is avg*n ) and 3*3 here we are taking after 3 years and into(*) 3 munbers. |

Praveen said: (Nov 30, 2010) | |

@SUNDER IN 2nd expression {y+5(10)}/6 is wrong i think . it has to be y*10+5*10 divided by 5 i think because father has died so only 5 members will be ther .. |

Ramya said: (Dec 3, 2010) | |

This is ramya from vizag,can i solve the problem as below as per question, present ages of hus=h;wife=w;child=c; ---> 3 years ago it was said the avg ages of the hus,wife,child was 27 years.so, ((h-3)+(w-3)+(c-3))/3=27; so solving it i got h+w+c=90;--->(a) and given 5 years ago wife and childs age avg=20years so, i took((w-5)+(c-5))/2=20;solving it i got w+c=50;-->(B) on solving (a)&(b) i got h age as 40years,can this procedure be correct?? please do reply me? |

Loverboy said: (Dec 19, 2010) | |

3 years ago,their avg is 27. ((h-3)+(w-3)+(c-3))/3=27 h+w+c=90.(present) 5 years ago w & c is 20. ((w-5)+(c-5))/2=20 w+c=50.(present) (h+w+c)-(w+c)=40. h=40 years |

Prasad said: (Jan 4, 2011) | |

@Ramya:this is one of the simplest way 2 solve such kind of problems.. |

Puja said: (Jan 19, 2011) | |

Yeah truly its very simple. Thanks. |

Sakshi said: (Mar 1, 2011) | |

Let the present age of husband,wife and child be x yrs 3 yrs ago their was x-3 x-3=27 x=30 the sum of their age is 90 5 yrs ago the avg age of wife n child was 20yrs their present avg age=20+5=25 so,the sum of their present age is 25*2=50 the present age of husband =90-50=40 |

Philip said: (Apr 27, 2011) | |

Ramya. Good way to solve, simple to understand. |

Karthika said: (May 3, 2011) | |

I solved in this method.. Is this right? Let x,y,z be the age of husband,wife and child respectively.. for the first condition.. we can write 27=((x+y+z)/3)-3 27=(x+y+z-9)/3 81=x+y+z-9 90=x+y+z....equation 1 for the second condition..we can write 20=((y+z)/2)-5 20=(y+z-10)/2 40=(y+z-10) 50=y+z........equation 2 equation1 - equation2 gives x+y+z-y-z=90-50 x=40 i.e husband's age is 40years.. |

Priya said: (Jun 24, 2011) | |

((h-3)+(w-3)+(c-3))/3=27 h+w+c=90. how to 90 comes ? I don't understand. |

Balaram said: (Jul 19, 2011) | |

@priya: Hi priya. Look into your equation, send 3 to right side which gives the equation, h,w,c are current ages of husband, wife and child respectively.... The average of their ages three years back is as follows. ((h-3)+(w-3)+(c-3))/3=81 ==> h+w+c=81+9 ==> h+w+c=90 ----(1)(this is the sum of ages of husband, wife and child at present) And further it is given that, five years back, average of wife and child is 20 years. i.e. ((w-5)+(c-5))/2=20 ==> (w-5)+(c-5)=40 ==> w+c=50----(2) Now, on substituting equation (2) in (1).. we will get h=90-50 = 40 years. Hence, the current age of husband is 40 years. Hope you would get it now. |

Hema said: (Aug 2, 2011) | |

Thanks ramya. |

Isha said: (Aug 20, 2011) | |

Its so easy ramya thanks. |

Ks Venkatesh said: (Aug 20, 2011) | |

Its simple: Avg of 6 family members before 10 years is (Hus-10)+(wife-10)+(fath-10)+(othrs-30)/6 at 10 years ago.. By simpllifing abv we get (hus+wife+fath+othrs-60)/6 Present age average(Here babe replaces father): (Hus+wif+Babe+others)/6 As per given condition equate both the abv equ: U'll get Father's age=60 years..!! QUITE EASY NA ?? |

Ravi said: (Sep 20, 2011) | |

Thanks ramya. |

Swathi said: (Sep 28, 2011) | |

1. A bus is started from the bustand at 8am and after staying 30min at a destination return back to the busstand.The destination is 27 miles from the busstand.The speed of the bus is 18mph.In return journey the bus travels with 50% fast speed.At what time it is return to the bus stand. a 11am b 1pm c 11pm d 10am 2. Person who decided to go to the weekend trip should not exceed 8hrs driving a day.Average speed of forward is 40mph.Due to the traffic in sunday in return journey average speed is 30mph.How far he can select a picnic spot? a 120 b 240 c 360 d 40 3. Find the value of @@+25-++@16,where @ denotes square and + denotes "square root"? 4. In a two dimensional array,X(9,7) with each element occupy 4 bytes of memory, with the address of the first element x(1,1) us 3000.find the address of x(8,5) Can anyone help me in finding the solution for this problem as soon as possible? |

Swathi said: (Sep 28, 2011) | |

10. In a two-dimensional array, X (9, 7), with each element occupying 4 bytes of memory, with address of the first element X (1, 1) is 3000; find the address of X (8, 5). 11. One boy can eat 100 chocolates in half a minute, and another can eat half as many in twice the length of time. How many chocolates can both boys eat in 15 seconds? 12. Potatoes are made up of 99% water and 1% "potato matter." Jack bought 100 pounds of potatoes and left them outside in the sun for a while. When he returned, he discovered that the potatoes had dehydrated and were now only made up of 98% water. How much did the potatoes now weight? 13. You own a pet store. If you put in one canary per cage, you have one canary too many. If you put in two canaries per cage, you have one cage too many. How many canaries and cages do you have? 14. Find the value of @@+25-++@16, where @ denotes "Square" and + denotes "square root". 15. A power unit is there by the bank of the river of 750 meters width. A cable is made from power unit to power plant opposite to that of the river and 1500mts away from the power unit. The cost of the cable Rs.12/- per meter. Find the total of laying the cable. 16. In Madras, temperature at noon varies according to -t^2/2 + 8t + 3, where t is elapsed time.Find how much temperature more or less in 4pm to 9pm. |

Yesu Babu Pagidimalla said: (Oct 7, 2011) | |

Average of present ages of h,w,c=27+3=30 Average of present ages of w,c =20+5=25 so age of husband = 90-50=40 |

Karthy said: (Jan 25, 2012) | |

When the solution is started like this husband=x,wife=y&child=z bf4 3yrs x-3+y-3+z-3/3 =27 terefore x+y+z=90--1 bf4 5yrs y-5+z-5/2 =20 terefore y+z=50---2 (1-2) terefore x=40 |

Vasavi said: (Mar 18, 2012) | |

Ramya your way of answering this was very good. |

Srinivas said: (Sep 27, 2012) | |

husband+wife+child =3 years ago =27 present age =30 (27+3=30) wife and child = 5 years ago =20 present age=25 (20+5=25) h+w+c =3*30=90 -- I w+c =2*25=50 --II substract(I-II) 90-50=40 year |

Rahul said: (Nov 9, 2012) | |

thanks ramya |

Ashwin said: (Aug 9, 2013) | |

H+W+C=81 is sum three year ago and W+C=40 five year ago. So five year ago it is wife and child sum is 40. Each year a 1 age will be added for a person. So W+C=44 after two years. (now W+C=44 is three year ago) so H+44 = 81. H = 37 three year ago. So at present his age is 37+3 = 40 = H. |

John Smith said: (Aug 14, 2013) | |

Present age of h+w+c = (27+3)*3 = 90. Present age of w+c = (20+5)*2 = 50. h's age = 90-50 = 40. |

Harpreet said: (Sep 11, 2013) | |

1. Av age of H+W+C=27. Three years back their total age, we multiply 27 by 3 = 81 years. Three years later age increased for three members = 3*3 = 9. 2. Current age of H+W+C = 90. 3. Av age of W+C = 20. Five years back their total age, we multiply 20 by 2 = 40. Five years later age increased for two members = 5*2 = 10. 4. Current age of W+C = 50. 5. Husband age = Current age of H+W+C-W+C = 90-50 = 40 years. |

Mahesh said: (Oct 3, 2013) | |

h+w+c/3 = 27. h+w+c = 81. w+c/2 = 20. w+c = 40. h+w+c = 81. h+40 = 81. h = 81-40. h = 40. |

Murali said: (Jan 9, 2014) | |

Given that average age of husband, wife, child 3 years ago was 27 years average age of wife child 5 years ago was 20 years. h+w+c/3 = 27. h+w+c = 81 it is 3 years ago this is eq1. w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2. Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age answer is 40 years. |

Shah said: (Feb 2, 2014) | |

(3x27)+3 [ 27 is avg. age x 3 family members + 3( ie number years ago) ... Ans comes to 85 years. (2x20)+5 [ 20 is avg. age of child and mother x 2 + 5( ie number years ago ... Ans comes to 45 years. Now 85-45 = 40 years. Is it correct way of solving ? |

Gopalkrishna said: (Jul 9, 2014) | |

Present age: H+W+C=30*3. W+C=25*2. .................... ie...,H=40 year. |

Aliyaz said: (Aug 16, 2014) | |

@PRIYA. [(h-3)+(w-3)+(c-3)/3] = 27. [(h+w+c-9)/3] = 27. [(h+w+c)/3]+(9/3) = 27. [(h+w+c)/3] = 27+3 ====>h+w+c=30*3 ====>h+w+c=90. Similarly w+c = 50. |

Kholofelo said: (Aug 27, 2014) | |

What is algorithm? |

Vijaykumar said: (Nov 12, 2014) | |

Good method to solve such type of question. |

Raj said: (Apr 27, 2015) | |

No need to add 3 to all. You have add 3 to avg it give avg age of all. Then age of three number = 30*3 = 90. Then add 5 to avg age of child and wife it gives present age i.e. 25. Age of two persons = 25*2 = 50. Age of husband = total age - two members age. 90 - 50 = 40. |

Ritu Sehgal said: (Jun 16, 2015) | |

Let husband present age - x. Let wife present age - y. Let son present age - z. The average age of husband, wife and son before 3 years was 27. i.e Before 3 year (x-3)+(y-3)+(z-3)/3 = 27. x-3+y-3+z-3 = 27*3. x+y+z = 81+9. x+y+z = 90.....(1). The average age of wife and son before 5 years was 20. i.e Before 5 years (y-5)+(z-5)/2 = 20. y-5+z-5 = 20*2. y+z = 40+10. y+z = 50....(2). Now by subtracting equation 2 from equation 1, we will find x = 40. |

Kesava said: (Oct 10, 2015) | |

1. Before 3 years husband+wife+child = 27. Now = 30*3 = 90. 2. Before 5 years wife+child = 20. Now = 25*2 = 50. Husband age = 90-50 = 40. |

Naseem Saifi said: (Jan 23, 2016) | |

Let age of husband, wife and child is x, y, z. Then 3 year ago age of husband, wife and child was x-3, y-3, z-z. Given that 3 year ago average of their age was 27. So (x-3+y-3+z-3) /3 = 27. => x+y+z-9 = 81. => x+y+z = 90____ (1). 5 year ago age of wife and child was y-5 and z-5. Given that 5 year ago average of their age was 20. So (y-5+z-5)/2 = 20. => y+z-10 = 40. => y+z = 50_______ (2). Now, (1) - (2). => x = 40. So age of husband is 40. |

Guhan said: (Mar 24, 2016) | |

Ramya it is very easy to understand. Keep solving the problem in the easiest way. |

Pbk said: (Apr 25, 2016) | |

@Swathi Answer for the !st problem. Given : 1) Going to destination: Distance = 27 miles. Speed = 18mph. 2)Return journey:- Distance= 27 miles Speed=50% faster than 18mph(given). So, Speed = 1/2*18 + 18 = 27. Speed =27mph. Halt of bus=30 minutes. Answer:- Let's first find the time to reach the destination:- Speed = Distance/time So, time = Distance/Speed Time =1.5 hr. Let's find time to return Time = Distance/Speed =27/27. = 1 hr. So total time taken to go and return = going time + 1/2 hr (halt) + return time. = 1.5 + 0.5 + 1 hr. = 3hr. So as journey began at 8 am So Bus will return at 8am+ 3hr=11am. Final Answer : a) 11am. |

Pbk said: (Apr 25, 2016) | |

@Swathi Answer for the 1st problem. Given : 1) Going to destination: Distance = 27 miles. Speed = 18mph. 2)Return journey:- Distance= 27 miles Speed=50% faster than 18mph(given). So, Speed = 1/2*18 + 18 = 27. Speed =27mph. Halt of bus=30 minutes. Answer:- Let's first find the time to reach the destination:- Speed = Distance/time So, time = Distance/Speed Time =1.5 hr. Let's find time to return Time = Distance/Speed =27/27. = 1 hr. So total time taken to go and return = going time + 1/2 hr (halt) + return time. = 1.5 + 0.5 + 1 hr. = 3hr. So as journey began at 8 am So Bus will return at 8am+ 3hr=11am. Final Answer : a) 11am. |

Amani said: (Jun 28, 2016) | |

Thanks for your easy explanation @Loverboy. |

Khasim said: (Jul 18, 2016) | |

@Ramya. Really a great explanation. Thank you. |

Karthick said: (Aug 2, 2016) | |

Average = sum/no of count. 27 = h + w + c/3. h + w + c = 81. 20 = w + c - 1/2. w + c = 41. h + 41 = 81. H = 40. |

Peter Nabam said: (Aug 5, 2016) | |

Thanks, @Karthick. |

Manoj Aravindh said: (Aug 6, 2016) | |

(H + W + C) - 3 * 3 -------------------------- = 27 3 (W + C) - 2 * 5 ------------------------- = 20 2 Solving this We get the solution. |

Ahmedshaonaiub said: (Aug 9, 2016) | |

5 years age child and wife Avg age was 20, so 3 years ago it was 22. There we find (27 * 3) - (22 + 22) = 37; 37 is the husbands age 3 years ago, So present year age => 37 + 3 = 40. |

Ganesh said: (Sep 2, 2016) | |

Nice method to find the solution @Ramya. |

Sam said: (Sep 15, 2016) | |

@Ramya your explanation is very useful. |

Anurag said: (Sep 17, 2016) | |

@Ramya your method is correct. |

Grace said: (Oct 12, 2016) | |

Tremendous @Ramya. |

Vikash said: (Dec 21, 2016) | |

@Ramya. Your explanation is good, thanks. |

Kiran said: (Apr 29, 2017) | |

Your explanation is extremely Good, thanks @Ramya. |

Kavi said: (Jul 10, 2017) | |

Please clarify my doubt. If my age is 10 before 3 years then at present my age should be 13. So it is (10+3) not (10-3) right. But why we subtracted 3 in above question? |

Jayant said: (Jul 11, 2017) | |

@Ramya, thanks for such a good and easy way. |

Ayesha said: (Aug 1, 2017) | |

Seven years ago at the time of their marriage, the average age of a man and his wife was 28 years. At present, they have two children. Their daughter is 2 years older than their son. One year after the birth of the daughter, the average age of the man, wife and their daughter was 21 years, then the present age of the son is. How do I solve this? Please help me. |

Subitha said: (Aug 8, 2017) | |

Thanks for your easy way of explanataion @Ramya. |

Yasir Aziz said: (Aug 12, 2017) | |

@Naseem. You gave the easy and best solution for this question. Thanks. |

Kalyan said: (Aug 21, 2017) | |

In the year 1950 the avg. Of 6 brothers is 15 years.The youngest brother died in 1957 at the age of 12 years.find the avg. Remaining in 1958? Can anyone solve this? |

Prakhar Malviya said: (Sep 5, 2017) | |

The presnet ages of 3 three. (x+y+z)/3=30 ---> eq1. Five years ago (y+z)/2=25 y+z=50 ---> eq.2. Put the values of y+z in thr first equation we get:- (x+50)/3=30, x=90-50, x=40. |

Ramya said: (Nov 27, 2017) | |

Thanks @Ramya. |

Ramya said: (Nov 27, 2017) | |

When I have married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me. The average age of my family during my marriage is same as today. What is the age of Father when he died? Can anyone solve this question in simple way? |

Farooq said: (Jan 13, 2018) | |

@ALL. Members average-years ago=average age. ((h+w+c)/3)-3=27.........=90. n0w average age of wife and child. ((w+c)/2)-5=20............=50, So, 90-50=40 years. |

Akki said: (Feb 22, 2018) | |

Fathers age is the sum of mother and his son age but the today's average age of three of them are 20 so what will be the today's age of father? Can anyone solve this? |

Suvitha said: (Apr 1, 2018) | |

3 years ago, average age of husband, wife and their child = 27, => Sum of age of husband, wife and their child before 3 years = 3 * 27 = 81, => (h-3) + (w-3) + (c-3) = 81, => h + w + c = 81 + 9 = 90 --- equation(1). 5 years ago, average age of wife and child = 20, => Sum of age of wife and child before 5 years = 2 * 20 = 40, => (w-5) + (c-5) = 40, => w + c = 40 + 10 = 50 --- equation(2). Substituting equation(2) in equation(1) => h + 50 = 90, => h = 90 - 50 = 40. i.e., Present age of the husband = 40. |

Krina said: (Apr 16, 2018) | |

Can anyone please help me with this question? The average of a couple was 24 years when the child was just born. What will be the age of the father when the child reaches to the age of the mother when she gave him the birth? |

Deeksha said: (May 5, 2018) | |

The age of mother and father when the child was just born is 24/2=12. When the child reaches to the age of the mother means when it will reach 12 years, Father age is 12+12=24. Can anyone say is this answer is correct? |

Anjana said: (May 6, 2018) | |

Thanks @Ramya. |

Sathish said: (Jun 17, 2018) | |

Thank you for explaining the answer. |

Himanshu Arora said: (Jun 20, 2018) | |

3 year ago(h+w+c) = 27 * 3 = 81. 5 year ago=81-6 = 75(2h+2w+2c). 5 year ago(w+c) = 2 * 20 = 40. 5 year ago h = 75-40 = 35. And the present age is 40 years of the husband. |

Salpal Satish Yadav said: (Jun 23, 2018) | |

First separate the question: In the first part, The average age of husband, wife and their 3 years ago was 27 years, so; Lets consider Husdand age = x-3(-3 because it was 3 years ago from the present age) Wife's age= y-3 and son's age = z-3, Average= x-3+y-3+z-3/3=27, x+y+z=81 ------> (1) Second part of the question. That of wife and the child 5 years ago was 20 years, so; Wife age years ago is y-5, Sons age is z-5, Avg= y-5+z-5=20, y+z=30---> (2) Equating (1) and (2) Then x=40. |

Ahir N.M said: (Jul 28, 2018) | |

The average age of a husband and wife at the time of their marriage was 25 years. A son was born to them exactly 2 years after their marriage and the average present age of all three is 24 years. How many years have been passed by the couple? Can anyone explain the answer of this? |

Kanchan Shah said: (Sep 14, 2018) | |

27*3=81, 81+9=90, 5year ago =formula( average age*2), So, 20*2=40, 40+10=50. Husband age 90 - 50 = 40. |

Nikhil said: (Sep 27, 2018) | |

@Kanchan Shah. Can you give the explanation little briefly? |

Ramesh said: (Oct 15, 2018) | |

Your explanation is superb, Thanks @RAMYA. |

Asad Ullah said: (Dec 19, 2018) | |

The average age of three persons is 18. If two of them are included then the average age becomes 20. If the age of 1st is 17 then find the age of the remaining persons. Can anyone tell me? |

Muskan said: (Dec 27, 2018) | |

The average age 3 years ago = x+y+z/3 = 27, Age of wife and son 5 years ago is x-2+y-2/2 = 20, Hence x+y = 36. 36+z/3 = 27, z=45. Hence present age should be 45+3 which is 48. Can someone tell me why this is wrong? |

Rida Akram said: (Mar 7, 2019) | |

A person has a wife and three children. The average age of his parents is 70 which is 40 to his age and his wife is 15 from the average age of her children. What is the average age of the whole family? Can anyone solve this? |

Ameer said: (Mar 19, 2019) | |

Thanks for providing the easiest solution @Loverboy. 3 years ago, their avg is 27. ((h-3) + (w-3) + (c-3) ) /3 = 27. h+w+c = 90. (present). 5 years ago w & c is 20. ((w-5) + (c-5) ) /2 = 20. w+c=50. (present). (h+w+c) - (w+c) = 40. h = 40 years. |

Mukul Kalsait said: (Apr 13, 2019) | |

20+5 =25 today's average of w+child. H+w+child is 27 +3 = 30 todays all average. Difference is 5, So 5*2+ new avg30 = 40. |

Anshal Mishra said: (Jul 2, 2019) | |

Thanks @Ramya. |

Sriram said: (Jul 15, 2019) | |

@All. Take x, y, z intial age is 27 after three years it converted into 30. For three members it is 90. Then 5 years back 20 years. Calculate with present age it is 25. Now X+Y+Z=(3*30)=90. Y+Z=20(5 years back)Now =(25*2)=50, Now equate it. Y+Z cancelled, X=90-50. And X=40. |

Ravikumara. said: (Sep 17, 2019) | |

a)=(x+y+z)/3 = 27------> (1) given =(x+y+z) =3*27=81------> (2) 3years back =(x+y+z) =81+(3*3) =90------> (3) present age. B) =(x+y) /2= 20------> (4) given = (x+y) =2*20=40------> (5) 5years back age = (x+y) =40+(5*2)=50------> (6) present age of wife and child. = x+y+z =90 = 50+z=90 =90-50 = 40 = z------> Present husband age (Or) eq-3 subtracting with 6 => 90-50 = 40 husband's present age. |

Sanya said: (Sep 19, 2019) | |

The average age of a husband and a wife is 30. What is the wife's age if the husband's age is 40? Can anyone solve this? |

Sanjay said: (Sep 29, 2019) | |

Thanks for explaining @Ramya. |

Sayed Sirajunnisa said: (Oct 5, 2019) | |

A family of six members bought a car 10 years ago, and had a road accident today, in which one of the family members died. The average age of the family at the time when they bought the car is same as of today. What was the age of the member who passed away?can anyone help me with this problem, I need solution to this Question. |

Shasi Kumar said: (Nov 19, 2019) | |

Five years ago, the average age of the Ram family has 5 members including Ram was 29 years. Ram got married 3 years ago and his only child was born 2 years after marriage so that the present average age of family becomes 28 years. Find the age of a bride at the time of marriage? |

Anant Gavas said: (Nov 30, 2019) | |

(H+W+C)/3 = 27+3(add 3 to get present data). H+W+C = 27*3+3*3 = 90. (W+C)/2 = 20+5(to get present data). W+C = 20*2+5*2 = 50. So (H+W+C)-(W+C) = 40 years. |

Sumit said: (Jan 23, 2020) | |

The avg of age of your parents are 35 and avg of age of three of yours is 8 less. What is your age? Please anyone answer this with explanation. |

Bharani said: (Feb 24, 2020) | |

Same question but find the wife age means how to solve? |

Mayuri Khode said: (Mar 30, 2020) | |

@Bharani. Instead of addition W+C you can replace it by H+C. i.e (H+W+C)-(H+C). |

Varshithtunuguntla said: (Apr 4, 2020) | |

Your answer is correct. Thanks @Ramya. |

Manoj Kumar said: (Jun 10, 2020) | |

@Varshithtunuguntla. How obtained here 90 and 40. How did the multiplication? Can you tell me? |

Ruthra said: (Jun 29, 2021) | |

Wonderful explanation, thanks @Ramya. |

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